1. Which of the following ligands is bidentate?
Answer:
Explanation:
C2O4^2- (oxalate) can bind to the central metal atom through two oxygen atoms, making it bidentate.
2. The number of unpaired electrons in [Fe(CN)6]^4- is:
Answer:
Explanation:
[Fe(CN)6]^4- has Fe2+ ion which has 3d6 configuration. Therefore, there is one unpaired electron.
3. The IUPAC name of [Ni(NH3)4][NiCl4] is:
Answer:
Explanation:
The correct name is derived based on the rules of nomenclature for coordination compounds.
4. In the complex [Fe(H2O)6]^3+, the oxidation state of Fe is:
Answer:
Explanation:
In the given complex, each water molecule is neutral. Therefore, the oxidation state of Fe is +3.
5. Which of the following is not a chelating ligand?
Answer:
Explanation:
CN- is a monodentate ligand and does not form ring structures with metal ions, so it's not chelating.
6. Which complex exhibits optical isomerism?
Answer:
Explanation:
The complex [Co(NH3)4Cl2]^+ can exist in two non-superimposable mirror images.
7. The coordination number of platinum in the complex [PtCl2(en)] is:
Answer:
Explanation:
The complex has two chlorine and one ethylenediamine ligand, which is bidentate. So, the coordination number is 4.
8. The hybridization of the metal in [Fe(CN)6]^3- is:
Answer:
Explanation:
The complex has an octahedral geometry, which corresponds to d2sp3 hybridization.
9. The compound which is both paramagnetic and colored is:
Answer:
Explanation:
[Mn(CN)6]^3- has unpaired electrons which make it paramagnetic and contribute to color.
10. The geometry of [Cu(NH3)4]^2+ is:
Answer:
Explanation:
[Cu(NH3)4]^2+ exhibits a square planar geometry due to the d9 configuration of Cu2+.
11. The number of sigma bonds formed by [Ni(CN)4]^2- is:
Answer:
Explanation:
The four CN- ligands each form a sigma bond with Ni.
12. Which of the following compounds will have zero crystal field stabilization energy (CFSE)?
Answer:
Explanation:
[Co(NH3)6]^3+ has a d6 configuration with no unpaired electrons in an octahedral field, leading to zero CFSE.
13. The ligand that can cause the splitting of d-orbitals in an octahedral field in increasing order is:
Answer:
Explanation:
The strength of the ligand in causing splitting follows the spectrochemical series.
14. The complex [NiCl4]^2- is:
Answer:
Explanation:
[NiCl4]^2- has unpaired electrons, making it paramagnetic, and also imparts color due to d-d transitions.
15. Which of the following ligands acts as an ambidentate ligand?
Answer:
Explanation:
SCN- can bind through either sulfur or nitrogen, making it an ambidentate ligand.
16. The metal ion present in chlorophyll is:
Answer:
Explanation:
Chlorophyll, the green pigment in plants, contains a Mg^2+ ion at its center.
17. The geometry of [Cr(NH3)2Cl4]^- is:
Answer:
Explanation:
[Cr(NH3)2Cl4]^- has a tetrahedral geometry around the Cr atom.
18. Which of the following compounds can exhibit linkage isomerism?
Answer:
Explanation:
Linkage isomerism can be shown by ambidentate ligands like NO2-.
19. Which of the following ligands can exhibit chelation?
Answer:
Explanation:
EDTA is a hexadentate ligand and can form rings with metal ions, exhibiting chelation.
20. Which of the following complexes will be least stable?
Answer:
Explanation:
The stability of the complex depends on the ligand's ability to cause splitting. Following the spectrochemical series, F- is a weak field ligand and will form the least stable complex.