Class 12 Maths MCQ – Inverse Trigonometric Functions

1. Which of the following is the principal value branch of sin⁻¹x?

a) [-π/2, π/2]
b) [0, π]
c) [0, 2π]
d) [-π, 0]

Answer:

a) [-π/2, π/2]

Explanation:

The principal value branch of sin⁻¹x is [-π/2, π/2].

2. If sin⁻¹x + sin⁻¹y = π/2, then y is equal to:

a) cos x
b) sin x
c) tan x
d) cosec x

Answer:

a) cos x

Explanation:

Using the property sin⁻¹x + cos⁻¹x = π/2, we get y = cos x.

3. The value of tan(sin⁻¹(3/5)) is:

a) 3/4
b) 4/3
c) 5/4
d) 4/5

Answer:

b) 4/3

Explanation:

Let sin⁻¹(3/5) = θ. Then, sin θ = 3/5 and cos θ = 4/5. tan θ = sin θ/cos θ = 4/3.

4. The principal value of cos⁻¹(-1/2) is:

a) π/3
b) 2π/3
c) π/2
d) π

Answer:

b) 2π/3

Explanation:

The principal value of cos⁻¹x lies in [0, π]. Therefore, for x = -1/2, it is 2π/3.

5. The domain of the function tan⁻¹x is:

a) [-1, 1]
b) (-∞, ∞)
c) [0, π]
d) (-π/2, π/2)

Answer:

b) (-∞, ∞)

Explanation:

The function tan⁻¹x is defined for all real values.

6. The range of the function sec⁻¹x is:

a) [0, π] excluding π/2
b) [0, 2π] excluding π/2
c) [0, π/2] union [π/2, π]
d) [-π/2, π/2]

Answer:

a) [0, π] excluding π/2

Explanation:

The function sec⁻¹x takes values in [0, π] but is not defined at π/2.

7. The value of sin⁻¹(0) is:

a) 0
b) π/2
c) π
d) 1

Answer:

a) 0

Explanation:

The inverse sine of 0 is 0.

8. If x = tan⁻¹(√3), then the value of sin(2x) is:

a) 1
b) 0
c) √3
d) 2

Answer:

b) 0

Explanation:

x = π/3. Using the double angle formula, sin(2x) = sin(2π/3) = 0.

9. The value of cos⁻¹(0) is:

a) π/4
b) π/3
c) π/2
d) 0

Answer:

c) π/2

Explanation:

The inverse cosine of 0 is π/2.

10. Which of the following is not defined?

a) sin⁻¹(2)
b) tan⁻¹(2)
c) sec⁻¹(2)
d) cos⁻¹(2)

Answer:

d) cos⁻¹(2)

Explanation:

The function cos⁻¹x is defined for x in [-1, 1].

11. The value of sin(tan⁻¹(1)) is:

a) √2/2
b) 1/√2
c) √3/2
d) 1/2

Answer:

a) √2/2

Explanation:

Let θ = tan⁻¹(1). Then, tan θ = 1 implies θ = π/4. Thus, sin(π/4) = √2/2.

12. The principal value of cot⁻¹(1) is:

a) π/4
b) π/3
c) π/2
d) π

Answer:

a) π/4

Explanation:

The principal value of cot⁻¹(1) is π/4.

13. The value of tan⁻¹(1) + cot⁻¹(1) is:

a) π/2
b) π
c) 2π
d) 3π/2

Answer:

b) π

Explanation:

tan⁻¹(1) is π/4 and cot⁻¹(1) is π/4. Their sum is π.

14. The domain of cos⁻¹x is:

a) [-1, 1]
b) (0, 1)
c) [0, π]
d) (-π/2, π/2)

Answer:

a) [-1, 1]

Explanation:

The function cos⁻¹x is defined for x in [-1, 1].

15. The range of sin⁻¹x is:

a) [0, π]
b) [-π/2, π/2]
c) [0, 2π]
d) [-π, 0]

Answer:

b) [-π/2, π/2]

Explanation:

The function sin⁻¹x has its values in [-π/2, π/2].

16. If sin(2x) = 1, then x is:

a) sin⁻¹(1/2)
b) cos⁻¹(1/2)
c) tan⁻¹(1/2)
d) cot⁻¹(1/2)

Answer:

a) sin⁻¹(1/2)

Explanation:

2x = π/2. Thus, x = π/4 = sin⁻¹(1/2).

17. The value of cos(sin⁻¹(1/2)) is:

a) 1/2
b) √3/2
c) √2/2
d) 0

Answer:

b) √3/2

Explanation:

Let θ = sin⁻¹(1/2). Then, sin θ = 1/2 and cos θ = √3/2.

18. The principal value of sec⁻¹(-1) is:

a) π/2
b) π
c) 0
d) -π/2

Answer:

b) π

Explanation:

The principal value of sec⁻¹(-1) is π.

19. Which of the following has the range of [0, π]?

a) sin⁻¹x
b) tan⁻¹x
c) cos⁻¹x
d) cot⁻¹x

Answer:

c) cos⁻¹x

Explanation:

The function cos⁻¹x takes values in [0, π].

20. If x = sin⁻¹(1/√2), then x is equal to:

a) π/4
b) π/3
c) π/6
d) π/2

Answer:

a) π/4

Explanation:

The inverse sine of 1/√2 is π/4.

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